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26x^2=2500
We move all terms to the left:
26x^2-(2500)=0
a = 26; b = 0; c = -2500;
Δ = b2-4ac
Δ = 02-4·26·(-2500)
Δ = 260000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{260000}=\sqrt{10000*26}=\sqrt{10000}*\sqrt{26}=100\sqrt{26}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-100\sqrt{26}}{2*26}=\frac{0-100\sqrt{26}}{52} =-\frac{100\sqrt{26}}{52} =-\frac{25\sqrt{26}}{13} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+100\sqrt{26}}{2*26}=\frac{0+100\sqrt{26}}{52} =\frac{100\sqrt{26}}{52} =\frac{25\sqrt{26}}{13} $
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